25q^2-10q-3=0

Solution for 25q^2-10q-3=0 equation:

Simplifying
25q2 + -10q + -3 = 0

Reorder the terms:
-3 + -10q + 25q2 = 0

Solving
-3 + -10q + 25q2 = 0

Solving for variable 'q'.

Factor a trinomial.
(-1 + -5q)(3 + -5q) = 0

Subproblem 1
Set the factor '(-1 + -5q)' equal to zero and attempt to solve:

Simplifying
-1 + -5q = 0

Solving
-1 + -5q = 0

Move all terms containing q to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + -5q = 0 + 1

Combine like terms: -1 + 1 = 0
0 + -5q = 0 + 1
-5q = 0 + 1

Combine like terms: 0 + 1 = 1
-5q = 1

Divide each side by '-5'.
q = -0.2

Simplifying
q = -0.2
Subproblem 2
Set the factor '(3 + -5q)' equal to zero and attempt to solve:

Simplifying
3 + -5q = 0

Solving
3 + -5q = 0

Move all terms containing q to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -5q = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -5q = 0 + -3
-5q = 0 + -3

Combine like terms: 0 + -3 = -3
-5q = -3

Divide each side by '-5'.
q = 0.6

Simplifying
q = 0.6
Solution
q = {-0.2, 0.6}